Algebra 1: Common Core (15th Edition)

Published by Prentice Hall
ISBN 10: 0133281140
ISBN 13: 978-0-13328-114-9

Chapter 8 - Polynomials and Factoring - Chapter Review - Page 538: 62



Work Step by Step

$9z^{2}-16=$ ...write each term as a square. $=(3z)^{2}-4^{2}$ ...factor using the rule for a difference of two squares. ($a^{2}-b^{2})=(a+b)(a-b),\qquad a=3z,\ b=4$) $=(3z-4)(3z+4)$
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