Answer
$8(2v+1)(2v-1)$
Work Step by Step
$32v^{2}-8=$
...factor out the GCF, $8$.
$=8(4v^{2}-1)$
...write $4v^{2}-1$ as a difference of two squares.
$a=2v,\quad b=1$
$=8(2v+1)(2v-1)$
Algebra 1: Common Core (15th Edition)
by Charles, Randall I.
Published by
Prentice Hall
ISBN 10:
0133281140
ISBN 13:
978-0-13328-114-9
Chapter 8 - Polynomials and Factoring - Chapter Review - Page 538: 69
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