# Chapter 8 - Polynomials and Factoring - Chapter Review - Page 538: 73

$3y^{2}$ , $1$

#### Work Step by Step

$6y^{3}-3y^{2}+2y-1=$ ...the first two terms: $6y^{3}=2\cdot(3\cdot y\cdot y)\cdot y$ $-3y^{2}=-1\cdot(3\cdot y\cdot y)$ GCF: $3y^{2}$ ...the last two terms. $2y=2\cdot y$ $1=1$ GCF: $1$ Answer: $3y^{2}$ , $1$

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