Algebra 1: Common Core (15th Edition)

Published by Prentice Hall
ISBN 10: 0133281140
ISBN 13: 978-0-13328-114-9

Chapter 8 - Polynomials and Factoring - 8-8 Factoring by Grouping - Practice and Problem-Solving Exercises - Page 533: 44


a. $2\pi x(x+3)^{2}$ b. $r=x+3$

Work Step by Step

a. $2\pi x^{3}+12\pi x^{2}+18\pi x=$ ...factor out the GCF. $=2\pi x(x^{2}+6x+9)$ ...write $(x^{2}+6x+9)$ as a square of a binomial. $=2\pi x(x+3)^{2}$ b. If $V=\pi r^{2}h$, and $V=2\pi x(x+3)^{2}$, then $h=2x,\ \pi=\pi$, which means that $r^{2}=(x+3)^{2}$ $r=x+3$
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