Algebra 1: Common Core (15th Edition)

Published by Prentice Hall
ISBN 10: 0133281140
ISBN 13: 978-0-13328-114-9

Chapter 8 - Polynomials and Factoring - 8-8 Factoring by Grouping - Practice and Problem-Solving Exercises - Page 533: 48

Answer

F

Work Step by Step

$2x^{3}\cdot x^{8}=$ ...multiplying the powers of $x$, we add exponents. $=2x^{3+8}$ ...simplify. $=2x^{11}$ Answer: F
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