## Algebra 1: Common Core (15th Edition)

$(6g^{3}-7h^{2})(5g^{2}+4h)$
$30g^{5}+24g^{3}h-35g^{2}h^{2}-28h^{3}=$ ...factor out the GCF from each pair of terms. $=6g^{3}(5g^{2}+6h)-7h^{2}(5g^{2}+4h)$ ...use the Distributive Property. $=(6g^{3}-7h^{2})(5g^{2}+4h)$