Answer
$(6g^{3}-7h^{2})(5g^{2}+4h)$
Work Step by Step
$30g^{5}+24g^{3}h-35g^{2}h^{2}-28h^{3}=$
...factor out the GCF from each pair of terms.
$=6g^{3}(5g^{2}+6h)-7h^{2}(5g^{2}+4h)$
...use the Distributive Property.
$=(6g^{3}-7h^{2})(5g^{2}+4h)$
Algebra 1: Common Core (15th Edition)
by Charles, Randall I.
Published by
Prentice Hall
ISBN 10:
0133281140
ISBN 13:
978-0-13328-114-9
Chapter 8 - Polynomials and Factoring - 8-8 Factoring by Grouping - Practice and Problem-Solving Exercises - Page 533: 43
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