Algebra 1: Common Core (15th Edition)

Published by Prentice Hall
ISBN 10: 0133281140
ISBN 13: 978-0-13328-114-9

Chapter 8 - Polynomials and Factoring - 8-8 Factoring by Grouping - Practice and Problem-Solving Exercises - Page 533: 45



Work Step by Step

$(2^{5}+2^{4}+2^{3})+(2^{2}+2^{1}+2^{0})$ ...factor each expression by grouping. $=2^{3}(2^{2}+2^{1}+2^{0})+2^{0}(2^{2}+2^{1}+2^{0})$ ...use the Distributive Property. $=(2^{3}+2^{0})(2^{2}+2^{1}+2^{0})$ ...simplify the powers of 2. $=(8+1)(4+2+1)$ ...simplify. $=(9)(7)$
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