Answer
$63=(9)(7)$
Work Step by Step
$(2^{5}+2^{4}+2^{3})+(2^{2}+2^{1}+2^{0})$
...factor each expression by grouping.
$=2^{3}(2^{2}+2^{1}+2^{0})+2^{0}(2^{2}+2^{1}+2^{0})$
...use the Distributive Property.
$=(2^{3}+2^{0})(2^{2}+2^{1}+2^{0})$
...simplify the powers of 2.
$=(8+1)(4+2+1)$
...simplify.
$=(9)(7)$
