Answer
$(p^{2}+q)(m+n^{5})$
Work Step by Step
$p^{2}m+p^{2}n^{5}+qm+qn^{5}=$
...factor out the GCF out of each pair of terms.
$=p^{2}(m+n^{5})+q(m+n^{5})$
...use the Distributive Property.
$=(p^{2}+q)(m+n^{5})$
Algebra 1: Common Core (15th Edition)
by Charles, Randall I.
Published by
Prentice Hall
ISBN 10:
0133281140
ISBN 13:
978-0-13328-114-9
Chapter 8 - Polynomials and Factoring - 8-8 Factoring by Grouping - Practice and Problem-Solving Exercises - Page 533: 42
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