Algebra 1: Common Core (15th Edition)

Published by Prentice Hall
ISBN 10: 0133281140
ISBN 13: 978-0-13328-114-9

Chapter 8 - Polynomials and Factoring - 8-7 Factoring Special Cases - Practice and Problem-Solving Exercises - Page 527: 48

Answer

$91=(7)(13)$

Work Step by Step

$91=$ ...write $91$ as a difference of two squares. $=100-9$ ...write each term as a square. $=10^{2}-3^{2}$ ...use the rule for the difference of two squares. $=(10-3)(10+3)$ ...simplify. $=(7)(13)$
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