Answer
$(3n+20)(3n-20)$
Work Step by Step
$9n^{2}-400=$
...write each term as a square.
$=(3n)^{2}-20^{2}$
...factor using the rule for a difference of two squares.
($a^{2}-b^{2}=(a+b)(a-b),\ a=3n,\ b=20$)
$=(3n+20)(3n-20)$
Algebra 1: Common Core (15th Edition)
by Charles, Randall I.
Published by
Prentice Hall
ISBN 10:
0133281140
ISBN 13:
978-0-13328-114-9
Chapter 8 - Polynomials and Factoring - 8-7 Factoring Special Cases - Practice and Problem-Solving Exercises - Page 527: 35
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