Answer
$5(4g+3)(4g-3)$
Work Step by Step
$80g^{2}-45=$
...factor out the GCF, $5$.
$=5(16g^{2}-9)$
...write the difference as $a^{2}-b^{2}$.
$=3[(4g)^{2}-3^{2}]$
...factor using the rule for a difference of two squares.
$=5(4g+3)(4g-3)$
Algebra 1: Common Core (15th Edition)
by Charles, Randall I.
Published by
Prentice Hall
ISBN 10:
0133281140
ISBN 13:
978-0-13328-114-9
Chapter 8 - Polynomials and Factoring - 8-7 Factoring Special Cases - Practice and Problem-Solving Exercises - Page 527: 38
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