Algebra 1: Common Core (15th Edition)

Published by Prentice Hall
ISBN 10: 0133281140
ISBN 13: 978-0-13328-114-9

Chapter 8 - Polynomials and Factoring - 8-7 Factoring Special Cases - Practice and Problem-Solving Exercises - Page 527: 30

Answer

$(2p+7)(2p-7)$

Work Step by Step

$4p^{2}-49=$ ...write each term as a square. $=(2p)^{2}-7^{2}$ ...factor using the rule for a difference of two squares. ($a^{2}-b^{2}=(a+b)(a-b),\ a=4p,\ b=7$) $=(2p+7)(2p-7)$
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