Algebra 1: Common Core (15th Edition)

Published by Prentice Hall

Chapter 8 - Polynomials and Factoring - 8-7 Factoring Special Cases - Practice and Problem-Solving Exercises - Page 527: 33

Answer

$(8q+9)(8q-9)$

Work Step by Step

$64q^{2}-81=$ ...write each term as a square. $=(8q)^{2}-9^{2}$ ...factor using the rule for a difference of two squares. ($a^{2}-b^{2}=(a+b)(a-b),\ a=8q,\ b=9$) $=(8q+9)(8q-9)$

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