## Algebra 1: Common Core (15th Edition)

The answer is $\frac{-3x^{\frac{1}{3}}z^{6}}{y^{\frac{1}{2}}}$
To solve = -3$x^{\frac{1}{3}}$$y^{-\frac{1}{2}}$$z^{6}$ --> To simplify this, we need to change the negative exponent to a positive exponent. = $\frac{-3x^{\frac{1}{3}}z^{6}}{y^{\frac{1}{2}}}$