Algebra 1: Common Core (15th Edition)

Published by Prentice Hall
ISBN 10: 0133281140
ISBN 13: 978-0-13328-114-9

Chapter 7 - Exponents and Exponential Functions - 7-2 Multiplying Powers With the Same Base - Practice and Problem-Solving Exercises - Page 431: 48


The answer is $2^{2n+3}$

Work Step by Step

To solve this = $2^{n}$$\times$$2^{n+2}$$\times$$2^{1}$. --> same base add all exponents = $2^{(n+(n+2)+(1))}$ = $2^{(n+n+2+1)}$ = $2^{2n+3}$
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