Algebra 1: Common Core (15th Edition)

Published by Prentice Hall
ISBN 10: 0133281140
ISBN 13: 978-0-13328-114-9

Chapter 7 - Exponents and Exponential Functions - 7-2 Multiplying Powers With the Same Base - Practice and Problem-Solving Exercises - Page 431: 50


The expression would be $\frac{1}{(a+b)}$

Work Step by Step

To solve = $(a+b)^{2}$$(a+b)^{-3}$ --> Since they have the same base, we can add the exponents. = $(a+b)^{2+(-3)}$ = $(a+b)^{(2-3)}$ = $(a+b)^{(-1)}$ = $\frac{1}{(a+b)}$
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