Algebra 1: Common Core (15th Edition)

To solve = (2$x^{\frac{1}{2}}$$y^{\frac{2}{3}})(4x^{\frac{1}{4}}$$y^{\frac{5}{6}}$) =(2$\times$4)($x^{\frac{1}{2}+\frac{1}{4}}$)($y^{\frac{2}{3}+\frac{5}{6}}$) = (8)($x^{\frac{2}{4}+\frac{1}{4}}$)($y^{\frac{4}{6}+\frac{5}{6}}$) = (8)($x^{\frac{3}{4}}$)($y^{\frac{9}{6}}$) = 8$x^{\frac{3}{4}}$$y^{\frac{3}{2}}$ The only answer that matches this is D, so D is the correct answer.