Algebra 1: Common Core (15th Edition)

Published by Prentice Hall
ISBN 10: 0133281140
ISBN 13: 978-0-13328-114-9

Chapter 7 - Exponents and Exponential Functions - 7-2 Multiplying Powers With the Same Base - Practice and Problem-Solving Exercises - Page 431: 49


The answer is $3^{\frac{5}{2}}$$\times$$2^{y+x}$

Work Step by Step

To solve this =$3^{\frac{1}{2}}$$\times$$2^{y}$$\times$$3^{2}$$\times$$2^{x}$. --> same base add all exponents = $3^{(\frac{1}{2}+2)}$$\times$$2^{(y+x)}$ = $3^{(\frac{1}{2}+\frac{4}{2})}$$\times$$2^{(y+x)}$ = $3^{\frac{5}{2}}$$\times$$2^{(y+x)}$
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