## Algebra 1: Common Core (15th Edition)

You do not replace the coins, so the events are dependent. 1 of the 9 coins is a nickel: P(nickel)=$\frac{1}{9}$ 0 of the 8 remaining coins is a nickel: P(nickel after nickel)=$\frac{0}{8}$=0 P(nickel then nickel)=P(nickel) $\times$ P(nickel after nickel) P(nickel then nickel)=$\frac{1}{9}$ $\times$ 0 P(nickel then nickel)=0