# Chapter 12 - Data Analysis and Probability - 12-8 Probability of Compound Events - Practice and Problem-Solving Exercises - Page 781: 33

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#### Work Step by Step

You do not replace the coins, so the events are dependent. 1 of the 9 coins is a nickel: P(nickel)=$\frac{1}{9}$ 0 of the 8 remaining coins is a nickel: P(nickel after nickel)=$\frac{0}{8}$=0 P(nickel then nickel)=P(nickel) $\times$ P(nickel after nickel) P(nickel then nickel)=$\frac{1}{9}$ $\times$ 0 P(nickel then nickel)=0

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