## Algebra 1: Common Core (15th Edition)

$\frac{1}{36}$
You do not replace the coins, so the events are dependent. 2 of the 9 coins are pennies: P(penny)=$\frac{2}{9}$ 1 of the 8 remaining coins is a quarter: P(quarter after penny)=$\frac{1}{8}$ P(penny then quarter)=P(penny) $\times$ P(quarter after penny) P(penny then quarter)=$\frac{2}{9}$ $\times$ $\frac{1}{8}$ P(penny then quarter)=$\frac{1}{36}$