Algebra 1: Common Core (15th Edition)

Published by Prentice Hall
ISBN 10: 0133281140
ISBN 13: 978-0-13328-114-9

Chapter 12 - Data Analysis and Probability - 12-8 Probability of Compound Events - Practice and Problem-Solving Exercises - Page 781: 28



Work Step by Step

You do not replace the coins, so the events are dependent. 2 of the 9 coins are pennies: P(penny)=$\frac{2}{9}$ 3 of the 8 remaining coins are dimes: P(dime after penny)=$\frac{3}{8}$ P(penny then dime)=P(penny) $\times$ P(dime after penny) P(penny then dime)=$\frac{2}{9}$ $\times$ $\frac{3}{8}$ P(penny then dime)=$\frac{1}{12}$
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