# Chapter 12 - Data Analysis and Probability - 12-8 Probability of Compound Events - Practice and Problem-Solving Exercises - Page 781: 27

$\frac{1}{36}$

#### Work Step by Step

You do not replace the coin, so the events are dependent. 1 of the 9 coins is a quarter: P(quarter)=$\frac{1}{9}$ 2 of the 8 remaining coins are pennies: P(penny after quarter)=$\frac{2}{8}$=$\frac{1}{4}$ P(quarter then penny)=P(quarter) $\times$ P(penny after quarter) P(quarter then penny)=$\frac{1}{9}$ $\times$ $\frac{1}{4}$ P(quarter then penny)=$\frac{1}{36}$

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