#### Answer

$\frac{1}{36}$

#### Work Step by Step

You do not replace the coin, so the events are dependent.
1 of the 9 coins is a quarter:
P(quarter)=$\frac{1}{9}$
2 of the 8 remaining coins are pennies:
P(penny after quarter)=$\frac{2}{8}$=$\frac{1}{4}$
P(quarter then penny)=P(quarter) $\times$ P(penny after quarter)
P(quarter then penny)=$\frac{1}{9}$ $\times$ $\frac{1}{4}$
P(quarter then penny)=$\frac{1}{36}$