Algebra 1: Common Core (15th Edition)

Published by Prentice Hall
ISBN 10: 0133281140
ISBN 13: 978-0-13328-114-9

Chapter 12 - Data Analysis and Probability - 12-8 Probability of Compound Events - Practice and Problem-Solving Exercises - Page 781: 26



Work Step by Step

You do not replace the coin, so the events are dependent. 3 of the 9 coins are dimes: P(dime) = $\frac{3}{9}$ 3 of the 8 remaining coins are nickles: $\frac{3}{8}$ P(nickle) = $\frac{3}{8}$ P(dime then nickle) = P(dime) x P(nickle) = $\frac{3}{9} \times \frac{3}{8}=\frac{9}{72}=\frac{1}{8}$
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