## Algebra 1: Common Core (15th Edition)

$\frac{1}{8}$
You do not replace the coin, so the events are dependent. 3 of the 9 coins are dimes: P(dime) = $\frac{3}{9}$ 3 of the 8 remaining coins are nickles: $\frac{3}{8}$ P(nickle) = $\frac{3}{8}$ P(dime then nickle) = P(dime) x P(nickle) = $\frac{3}{9} \times \frac{3}{8}=\frac{9}{72}=\frac{1}{8}$