#### Answer

$=\frac{1}{2a^2-3}$

#### Work Step by Step

$\frac{5a^2}{10a^4-15a^2}$
$=\frac{5a^2}{5a^2(2a^2-3)}$
$=\frac{1}{2a^2-3}$

Published by
Prentice Hall

ISBN 10:
0133281140

ISBN 13:
978-0-13328-114-9

$=\frac{1}{2a^2-3}$

$\frac{5a^2}{10a^4-15a^2}$
$=\frac{5a^2}{5a^2(2a^2-3)}$
$=\frac{1}{2a^2-3}$

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