Answer
$=\frac{2c-9}{2c+8}$
Work Step by Step
$\frac{4c^2-36c+81}{4c^2-2c-72}$
$=\frac{(2c-9)(2c-9)}{(2c+8)(2c-9)}$
$=\frac{2c-9}{2c+8}$
Algebra 1: Common Core (15th Edition)
by Charles, Randall I.
Published by
Prentice Hall
ISBN 10:
0133281140
ISBN 13:
978-0-13328-114-9
Chapter 11 - Rational Expressions and Functions - 11-2 Multiplying and Dividing Rational Expressions - Practice and Problem-Solving Exercises - Page 676: 76
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