Algebra 1: Common Core (15th Edition)

$\frac{9m^{2}(m+1)}{2}$
Given : $\frac{3m^{3}-3m}{4m^{2}+4m-8} \times (6m^{2}+12m)$ $= \frac{3m(m-1)(m+1)}{4(m-1)(m+2)} \times 6m(m+2)$ $= \frac{9m^{2}(m+1)}{2}$ (After dividing out the common factors (m-1) and (m+2))