Algebra 1: Common Core (15th Edition)

Published by Prentice Hall
ISBN 10: 0133281140
ISBN 13: 978-0-13328-114-9

Chapter 11 - Rational Expressions and Functions - 11-2 Multiplying and Dividing Rational Expressions - Practice and Problem-Solving Exercises - Page 676: 64


$\frac{x+2}{4(x+7)}, with$ $x\ne-7$

Work Step by Step

Given : $\frac{x-5}{3x+2} \times \frac{3x+2}{4} \times \frac{x+2}{x^{2}+2x-35}$ This becomes : $\frac{x-5}{3x+2} \times \frac{3x+2}{4} \times \frac{x+2}{(x+7)(x-5)}$ $= \frac{x+2}{4(x+7)}$ (After dividing out the common factors (x-5) and (3x+2))
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