Answer
$=\frac{6v-7w}{3v-2w}$
Work Step by Step
$\frac{36v^2-49w^2}{18v^2+9vw-14w^2}$
$=\frac{(6v-7w)(6v+7w)}{18v^2+21vw-12vw-14w^2}$
$=\frac{(6v-7w)(6v+7w)}{(3v-2w)(6v+7w)}$
$=\frac{6v-7w}{3v-2w}$
The denominator of the original expression is 0 when $v = \frac{2}{3}w$ or $v = -\frac{7}{6}w$. So the simplified form is $=\frac{6v-7w}{3v-2w}$, where $v \ne \frac{2}{3}w$.
