Answer
$-\frac{3c^{2}+5c}{5c+4}$
In the original equation, the denominator becomes zero when $c=\frac{-4}{5}$ or $c=2$
Work Step by Step
Given expression : $\frac{-c(3c^{2}-c-10)}{(5c^{2}-6c-8)}$
(After factoring out -c from the numerator)
This becomes : $\frac{-c(3c+5)(c-2)}{(5c+4)(c-2)}$
(Factor the numerator and the denominator)
= $\frac{-c(3c+5)}{(5c+4)}$
= $-\frac{3c^{2}+5c}{5c+4}$
