## Algebra 1: Common Core (15th Edition)

$-\frac{3c^{2}+5c}{5c+4}$ In the original equation, the denominator becomes zero when $c=\frac{-4}{5}$ or $c=2$
Given expression : $\frac{-c(3c^{2}-c-10)}{(5c^{2}-6c-8)}$ (After factoring out -c from the numerator) This becomes : $\frac{-c(3c+5)(c-2)}{(5c+4)(c-2)}$ (Factor the numerator and the denominator) = $\frac{-c(3c+5)}{(5c+4)}$ = $-\frac{3c^{2}+5c}{5c+4}$