Algebra 1: Common Core (15th Edition)

Published by Prentice Hall
ISBN 10: 0133281140
ISBN 13: 978-0-13328-114-9

Chapter 11 - Rational Expressions and Functions - 11-1 Simplifying Rational Expressions - Practice and Problem-Solving Exercises - Page 668: 39


$-\frac{3c^{2}+5c}{5c+4}$ In the original equation, the denominator becomes zero when $c=\frac{-4}{5}$ or $c=2$

Work Step by Step

Given expression : $\frac{-c(3c^{2}-c-10)}{(5c^{2}-6c-8)}$ (After factoring out -c from the numerator) This becomes : $\frac{-c(3c+5)(c-2)}{(5c+4)(c-2)}$ (Factor the numerator and the denominator) = $\frac{-c(3c+5)}{(5c+4)}$ = $-\frac{3c^{2}+5c}{5c+4}$
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