Answer
$\frac{5w}{ 5w+6 }$.
Work Step by Step
$A_1=5w\cdot 5w$.
Area of the isosceles trapezium:
$A_2=\frac{1}{2}\left( 5w+6+6+5w \right )\left( 5w \right )$
Simplify.
$A_2=\frac{1}{2}\left( 10w+12 \right )\left( 5w \right )$
$A_2=\left( 5w+6 \right )\left( 5w \right )$
Ratio $=\frac{A_1}{A_2}$
Substitute values.
$=\frac{5w\cdot 5w}{\left( 5w+6 \right )\left( 5w \right )}$
Cancel common terms.
$=\frac{5w}{ 5w+6 }$.
