Algebra 1: Common Core (15th Edition)

Published by Prentice Hall
ISBN 10: 0133281140
ISBN 13: 978-0-13328-114-9

Chapter 11 - Rational Expressions and Functions - 11-1 Simplifying Rational Expressions - Practice and Problem-Solving Exercises - Page 668: 45



Work Step by Step

Given expression : $\frac{(x+3)(x+2)}{(x-4)(x+3)}$ Note that $x=-3$ and $x=4$ are excluded from the solution, as they would cause the denominator to be 0. = $\frac{x(x+2)+3(x+2)}{x(x+3)-4(x+3)}$ =$\frac{x^{2}+2x+3x+6}{x^{2}+3x-4x-12}$ This becomes : $\frac{x^{2}+5x+6}{x^{2}-x-12}$
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