Materials Science and Engineering: An Introduction

Published by Wiley
ISBN 10: 1118324579
ISBN 13: 978-1-11832-457-8

Chapter 12 - Structures and Properties of Ceramics - Questions and Problems - Page 508: 12.52b


$σ_{fs} = 43.82 MPa$

Work Step by Step

Given: Refer to the given Table. From Item 12.52a, $σ_{0} = 59.86 MPa$, n = 1.56 Required: Flexural strength for a 0.20 volume fraction porosity. Solution: Rearranging Equation 12.10: $σ_{fs} = σ_{0} e^{(-nP)} = (59.86 MPa) e^{[-(1.56)(.20)] }= 43.82 MPa$
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