Materials Science and Engineering: An Introduction

Published by Wiley
ISBN 10: 1118324579
ISBN 13: 978-1-11832-457-8

Chapter 12 - Structures and Properties of Ceramics - Questions and Problems - Page 508: 12.51b

Answer

$P$= 0.14 or 14 vol%

Work Step by Step

Required: Compute the volume fraction porosity at which the flexural strength for MgO is 74 MPa From 12.51a, $σ_{0} = 126.66 MPa $ and n =3.75. Solution: Using Equation 12.10 to compute value for $P$: $ln σ_{fs} = ln σ_{0} - nP $ $P = \frac{ln σ_{0} - ln σ_{fs}}{n} = \frac{ln (126.66 MPa) - ln (74 MPa)}{3.75} $= 0.14 or 14 vol%
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