Materials Science and Engineering: An Introduction

Published by Wiley
ISBN 10: 1118324579
ISBN 13: 978-1-11832-457-8

Chapter 12 - Structures and Properties of Ceramics - Questions and Problems - Page 508: 12.49b

Answer

$E = 194.50 GPa$

Work Step by Step

Given: The modulus of elasticity for spinel $(MgAl_{2}O_{4})$ having 5 vol% porosity is 240 GPa ($35 \times 10 ^{6} psi$). Required: Modulus of elasticity for 15 vol% porosity. Solution: Using Equation 12.9: $E =E_{0}(1 -1.9P + 0.9P^{2}) =(264.54 GPa)(1 -1.9(0.15) + 0.9(0.15)^{2}) = 194.50 GPa$
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