Materials Science and Engineering: An Introduction

$E_{0} = 341.69 GPa$
Given: The modulus of elasticity for titanium carbide (TiC) having 5 vol% porosity is 310 GPa. Required: Modulus of elasticity for the nonporous material Solution: Using Equation 12.9; $E_{0} =\frac{E}{(1 -1.9P + 0.9P^{2})} = \frac{(310 GPa)}{(1 -1.9(0.05) + 0.9(0.05)^{2})} = 341.69 GPa$