Answer
(a) $3.2\times 10^{-13}m$
(b) $0.243\times 10^{-11}m$
(c) $4.86\times 10^{-12}m$
Work Step by Step
(a) We can find the required change in wavelength as follows:
$\Delta \lambda=\frac{h}{m_ec}(1-cos\theta)$
We plug in the known values to obtain:
$\Delta \lambda=\frac{6.63\times 10^{-34}}{9.1\times 10^{-31}\times 3\times 10^8}(1-cos30^{\circ})=3.2\times 10^{-13}m$
(b) We can find the required change in wavelength as follows:
$\Delta \lambda=\frac{h}{m_ec}(1-cos\theta)$
We plug in the known values to obtain:
$\Delta \lambda=\frac{6.63\times 10^{-34}}{9.1\times 10^{-31}\times 3\times 10^8}(1-cos90^{\circ})=0.243\times 10^{-11}m$
(c) We can find the required change in wavelength as follows:
$\Delta \lambda=\frac{h}{m_ec}(1-cos\theta)$
We plug in the known values to obtain:
$\Delta \lambda=\frac{6.63\times 10^{-34}}{9.1\times 10^{-31}\times 3\times 10^8}(1-cos180^{\circ})=4.86\times 10^{-12}m$
