Physics Technology Update (4th Edition)

Published by Pearson
ISBN 10: 0-32190-308-0
ISBN 13: 978-0-32190-308-2

Chapter 30 - Quantum Physics - Problems and Conceptual Exercises - Page 1075: 43

Answer

$0.815\frac{m}{s}$

Work Step by Step

We know that $p=\frac{h}{\lambda}$ $p=\frac{6.63\times 10^{-34}}{486\times 10^{-9}}$ $p=1.36\times 10^{-27}Kg.\frac{m}{s}$ As $p=m_hv$ We plug in the known values to obtain: $1.36\times 10^{-27}=1.76\times 10^{-27}v$ $\implies v=0.815\frac{m}{s}$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.