Physics Technology Update (4th Edition)

Published by Pearson
ISBN 10: 0-32190-308-0
ISBN 13: 978-0-32190-308-2

Chapter 30 - Quantum Physics - Problems and Conceptual Exercises - Page 1075: 42

Answer

$3.25\frac{m}{s}$

Work Step by Step

We know that $p=\frac{h}{\lambda}$ $p=\frac{6.63\times 10^{-34}}{122\times 10^{-9}}$ $p=5.43\times 10^{-27}Kg.\frac{m}{s}$ As $p=m_hv$ We plug in the known values to obtain: $5.43\times 10^{-27}=1.67\times 10^{-27}v$ $\implies v=3.25\frac{m}{s}$
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