Answer
a) The momentum of blue light is greater than red light.
b) $p=1.75\times 10^{-27}Kg.\frac{m}{s}$
Work Step by Step
(a) As $momentum \propto frequency$ and the frequency of blue light is higher than that of the red light, we know that the momentum of blue light is greater than red light.
(b) We can find the momentum for red light as
$p=\frac{hf}{c}$
We plug in the known values to obtain:
$p=\frac{6.63\times 10^{-34}\times 4.0\times 10^{14}}{3\times 10^8}$
$p=8.84\times 10^{-28}Kg.\frac{m}{s}$
We can find the momentum for blue light as
$p=\frac{hf}{c}$
We plug in the known values to obtain:
$p=\frac{6.63\times 10^{-34}\times 7.9\times 10^{14}}{3\times 10^8}$
$p=1.75\times 10^{-27}Kg.\frac{m}{s}$
