Physics Technology Update (4th Edition)

Published by Pearson
ISBN 10: 0-32190-308-0
ISBN 13: 978-0-32190-308-2

Chapter 30 - Quantum Physics - Problems and Conceptual Exercises - Page 1075: 40

Answer

$6.08\times 10^{-7}m$

Work Step by Step

We can determine the required wavelength as follows: $\lambda=\frac{h}{m_ev_e}$ We plug in the known values to obtain: $\lambda=\frac{6.63\times 10^{-34}J.s}{(9.11\times 10^{-31}Kg)(1200m/s)}$ $\lambda=6.08\times 10^{-7}m$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.