Physics Technology Update (4th Edition)

Published by Pearson
ISBN 10: 0-32190-308-0
ISBN 13: 978-0-32190-308-2

Chapter 30 - Quantum Physics - Problems and Conceptual Exercises - Page 1075: 62

Answer

$14.07\times 10^2\frac{m}{s}$

Work Step by Step

We know that $\lambda=\frac{h}{p}=\frac{h}{mv}$ This can be rearranged as $v=\frac{h}{m\lambda}$ We plug in the known values to obtain: $v=\frac{6.63\times 10^{-34}}{1.67\times 10^{-27}\times 0.282\times 10^{-9}}$ $v=14.07\times 10^2\frac{m}{s}$
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