## Chemistry: The Central Science (13th Edition)

Published by Prentice Hall

# Chapter 3 - Chemical Reactions and Reaction Stoichiometry - Exercises: 3.47a

CSCl2

#### Work Step by Step

We have 10.4% C, 27.8% S and 61.7% Cl. First we assume 100g basis to make the masses easier. Then we have 10.4 g C, 27.8g S and 61.7g Cl Now we need to convert to moles so we have C is 12g/mol so 10.4g is 0.866 mol S is 32 g/mol so 27.8g is 0.866 mol Cl is 35.5 g/mol so 61.7g is 1.74 mol Then we divide each by the smallest number, 0.866 and get 0.866/0.866 = 1 0.866/0.866 = 1 1.74/0.866 = 2 Then the ratio is 1:1:2 so we have CSCl2

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