Answer
There are $ 3.70 \times 10^{19} \space S \space atoms$ in 5.00 mg of allicin.
Work Step by Step
1. As we have calculated in the last exercise:
There are $ 1.85 \times 10^{19}$ allicin molecules in 5.00 mg of that substance.
Thus, we just need to find a conversion factor between allicin molecules and $S$ atoms.
- According to the molecular formula of allicin: $C_6H_{10}OS_2$, each molecule has 2 sulfur atoms:
Allicin molecules to sulfur atoms: $\frac{2 \space S \space atoms}{1 \space allicin \space molecule}$
2. Calculate the number of $S$ atoms:
$1.85 \times 10^{19} \space allicin \space molecules \times \frac{2 \space S \space atoms}{1 \space allicin \space molecule} =$
$ 3.70 \times 10^{19} \space S \space atoms$
