## Chemistry: The Central Science (13th Edition)

Published by Prentice Hall

# Chapter 3 - Chemical Reactions and Reaction Stoichiometry - Exercises: 3.51a

C6H12

#### Work Step by Step

The empirical formula is CH2. Carbon is 12 g/mol H is 1 g/mol and there are 2 so 2*1 = 2 This is a total of 14 g/mol. If the molar mass is 84 then 84/14 = 6 so we multiply the empirical formula by 6 C6H12

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