Chemistry: The Central Science (13th Edition)

by Brown, Theodore E.; LeMay, H. Eugene; Bursten, Bruce E.; Murphy, Catherine; Woodward, Patrick; Stoltzfus, Matthew E.

Published by Prentice Hall

ISBN 10: 0321910419

ISBN 13: 978-0-32191-041-7

Chapter 3 - Chemical Reactions and Reaction Stoichiometry - Exercises - Page 115: 3.37b

Answer

$0.005738$ mol

Work Step by Step

Aluminum chloride has a molar mass of 133.33. Therefore .2550g of AlCl3 corresponds to $.2550/133.33=.001913$ mol AlCl3. Since there are three moles of chloride atoms for every one mole of AlCl3, the number of moles of cholride ions is $.001913*3=.005738$ mol

Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.

GradeSaver will pay $15 for your literature essays

GradeSaver will pay $25 for your college application essays

GradeSaver will pay $50 for your graduate school essays – Law, Business, or Medical

GradeSaver will pay $10 for your Community Note contributions

GradeSaver will pay $500 for your Textbook Answer contributions