# Chapter 3 - Chemical Reactions and Reaction Stoichiometry - Exercises: 3.47b

C3OF6

#### Work Step by Step

We have 21.7 % C, 9.6 % O, 68.7 % F We assume a 100g basis and then we have 21.7g C, 9.6g O and 68.7g F Then we need to convert to moles so C is 12g/mol then 21.7g is 1.81 mole O is 16 g/mol then 9.6g is 0.6 mole F is 18.998 g/mol then 68.7g is 3.6 mole We divide each by the smallest number, 0.6 and get 1.81/0.6 = 3 0.6/0.6 = 1 3.6/0.6 = 6 The ratio is 3:1:6 so we have C3OF6

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