Answer
Na3AlF6
Work Step by Step
We have 32.79 % Na, 13.02% Al and the remainder (100 - 32.79 - 13.02 = 54.19%) F.
We assume 100g basis so we have
32.79g Na, 13.02g Al and 54.19g F
Then we convert to moles so
Na is 22.99 g/mol then 32.79g is 1.43 mole
Al is 26.98 g/mol so 13.02g is 0.483 mole
F is 18.998 so 54.19g is 2.84 mole
we divide each by the smallest number, 0.483
1.43/0.483 = 3
0.483/0.483 = 1
2.84/0.483 = 6
The ratio is 3:1:6 so we have
Na3AlF6
