Chemistry: The Central Science (13th Edition)

by Brown, Theodore E.; LeMay, H. Eugene; Bursten, Bruce E.; Murphy, Catherine; Woodward, Patrick; Stoltzfus, Matthew E.

Published by Prentice Hall

ISBN 10: 0321910419

ISBN 13: 978-0-32191-041-7

Chapter 3 - Chemical Reactions and Reaction Stoichiometry - Exercises - Page 115: 3.35b

Answer

0.767 moles

Work Step by Step

Zn(NO3)2 Zinc is 65.38 N is 14 and there are 2 so 2*14 = 28 O is 16 and there are 6 so 6*16 = 96 65.38+28+96 = 189.38 Then there are 145.30g so to find the moles we do: 145.30g * (1mol/189.38grams) = 0.767 moles

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