Chemistry: The Central Science (13th Edition)

Published by Prentice Hall
ISBN 10: 0321910419
ISBN 13: 978-0-32191-041-7

Chapter 3 - Chemical Reactions and Reaction Stoichiometry - Exercises: 3.41c

Answer

3.46 x 10^-4 moles

Work Step by Step

We have 2.08 x 10^20 glucose molecules. 1 mole of molecules would be 6.022 x 10^23 molecules so we have : 2.08 x 10^20 molecules * (1 mole/ 6.022 x 10^23 molecules) = 3.46 x 10^-4 moles
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