Answer
There is a total of 232 g in 2.25 mole of $NaBr$
Work Step by Step
1. Determine the molar mass of this compound (NaBr), and setup the conversion factors:
Molar mass :
$Na: 22.99g $
$Br: 79.9g$
22.99g + 79.9g = 102.9g
$ \frac{1 \space mole \space (NaBr)}{ 102.9 \space g \space (NaBr)}$ and $ \frac{ 102.9 \space g \space (NaBr)}{1 \space mole \space (NaBr)}$
2. Calculate the mass:
$ 2.25 \space mole \times \frac{ 102.9 \space g}{1 \space mole} = 232 \space g$
